Each number specifies the distance between two dots. What we need is the following picture, where each dot is annotated with the distance to the left-most dot:
;; relative-2-absolute : (listof number) -> (listof number) ;; to convert a list of relative distances to a list of absolute distances ;; the first item on the list represents the distance to the origin (define (relative-2-absolute alon) (cond [(empty? alon) empty] [else (cons (first alon) (add-to-each (first alon) (relative-2-absolute (rest alon))))]));; add-to-each : number (listof number) -> (listof number) ;; to add n to each number on alon (define (add-to-each n alon) (cond [(empty? alon) empty] [else (cons (+ (first alon) n) (add-to-each n (rest alon)))]))
Developing a program that performs this calculation is at this point an
exercise in structural function design. Figure
contains the complete Scheme program. When the given list is not
empty, the natural recursion computes the absolute distance of the
remainder of the dots to the first item on (rest alon). Because
the first item is not the actual origin and has a distance of
(first alon) to the origin, we must add (first alon) to
each and every item on the result of the recursive application. This second
step, adding a number to each item on a list of numbers, requires an
auxiliary function.
While the development of the program is straightforward, using it on larger
and larger lists reveals a problem. Consider the evaluation of the
following definition:
(define x (relative-2-absolute (list 0 ... N)))As we increase N, the time needed grows even faster:
Instead of doubling as we go from 100 to 200 items, the time quadruples. This is also the approximate relationship for going from 200 to 400, 300 to 600, and so on.
Exercise 30.1.1
Reformulate add-to-each using map and lambda. Solution
Exercise 30.1.2
Determine the abstract running time of relative-2-absolute.
Hint: Evaluate the expression
(relative-2-absolute (list 0 ... N))by hand. Start by replacing N with 1, 2, and 3. How many natural recursions of relative-2-absolute and add-to-each are required each time? Solution
Considering the simplicity of the problem, the amount of ``work'' that the two functions perform is surprising. If we were to convert the same list by hand, we would tally up the total distance and just add it to the relative distances as we take another step along the line.
Let's attempt to design a second version of the function that is closer to our hand method. The new function is still a list-processing function, so we start from the appropriate template:
(define (rel-2-abs alon)
(cond
[(empty? alon) ...]
[else ... (first alon) ... (rel-2-abs (rest alon)) ...]))
Now imagine an ``evaluation'' of (rel-2-abs (list 3 2 7)):
(rel-2-abs (list 3 2 7))The first item of the result list should obviously be 3, and it is easy to construct this list. But, the second one should be (+ 3 2), yet the second instance of rel-2-abs has no way of ``knowing'' that the first item of the original list is 3. The ``knowledge'' is lost.= (cons ... 3 ... (convert (list 2 7)))
= (cons ... 3 ... (cons ... 2 ... (convert (list 7))))
= (cons ... 3 ... (cons ... 2 ... (cons ... 7 ... (convert empty))))
Put differently, the problem is that recursive functions are independent of their context. A function processes the list L in (cons N L) in the exact same manner as L in (cons K L). Indeed, it would also process L in that manner if it were given L by itself. While this property makes structurally recursive functions easy to design, it also means that solutions are, on occasion, more complicated than necessary, and this complication may affect the performance of the function.
To make up for the loss of ``knowledge,'' we equip the function with an additional parameter: accu-dist. The new parameter represents the accumulated distance, which is the tally that we keep when we convert a list of relative distances to a list of absolute distances. Its initial value must be 0. As the function processes the numbers on the list, it must add them to the tally.
Here is the revised definition:
(define (rel-2-abs alon accu-dist)
(cond
[(empty? alon) empty]
[else (cons (+ (first alon) accu-dist)
(rel-2-abs (rest alon) (+ (first alon) accu-dist)))]))
The recursive application consumes the rest of the list and the new
absolute distance of the current point to the origin. Although this means
that two arguments are changing simultaneously, the change in the second
one strictly depends on the first argument. The function is still a plain
list-processing procedure.
Evaluating our running example with rel-2-abs shows how much the use of an accumulator simplifies the conversion process:
= (rel-2-abs (list 3 2 7) 0) = (cons 3 (rel-2-abs (list 2 7) 3)) = (cons 3 (cons 5 (rel-2-abs (list 7) 5))) = (cons 3 (cons 5 (cons 12 (rel-2-abs empty 12)))) = (cons 3 (cons 5 (cons 12 empty)))Each item in the list is processed once. When rel-2-abs reaches the end of the argument list, the result is completely determined and no further work is needed. In general, the function performs on the order of N natural recursion steps for a list with N items.
One minor problem with the new definition is that the function consumes two
arguments and is thus not equivalent to relative-2-absolute, a
function of one argument. Worse, someone might accidentally misuse
rel-2-abs by applying it to a list of numbers and a number that
isn't 0. We can solve both problems with a function definition
that contains rel-2-abs in a local definition: see
figure
.
Now, relative-2-absolute and
relative-2-absolute2 are indistinguishable.